An electron initially at rest is accelerated over a distance of 0.290 m in 30.7 ns....
An electron initially at rest is accelerated over a distance of 0.290 m in 30.7 ns. Assuming its acceleration is constant, what voltage was used to accelerate it?
_________ V
Homework Answers
First we need the new velocity after the acceleration
Apply d = (.5)(vf + vo)t
.29 = (.5)(vf + 0)(30.7 X 10-9)
vf = 1.89 X 107 m/s
Then by the conservation of energy
PE = KE
qV = .5mv2
(1.6 X 10-19)V = (.5)(9.11 X 10-31)(1.89 X 107)2
V = 1016 V
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