Question

Calculate deltaHr for the reaction: C3H8(g) + 5O2(g)----->3CO2(g) + 4H2O(l)

Given:

3C(s) + 4H2(g)----->C3H8(g) deltaH -24.8 kcal

H2(g) + 1/2 O2(g)----->H2O(l) deltaH -68.3kcal

C(s) + O2(g)-------> CO2(g) deltaH -94.0 kcal

Let the reactions be numbered 1 to 4 from top to bottom

we need to find deltaHr for reaction 1

reaction 1 can be written as = - reaction 2 +4*reaction 3+ 3* reaction 4
so,
deltaHr (1) = -deltaHr (2) + 4*deltaHr (3) + 3*deltaHr (4)
= - (-24.8) + 4*(-68.3) + 3*(-94)
= 24.8 - 273.2 - 282
= -530.4 Kcal

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