


The rigid body shown below rotates around a fixed axis at O and position angle 0=...
Uniform bar OA rotates around endpoint O and position angle 0= 0 when the bar is horizontal and in static equilibrium. The mass of the bar is m = 20 kg, the length of the bar is L=1.2 m , k= 6000 N/m for the spring, and c= 320 N-s/m for the damper. The bar is initially at rest with 0 0 when force F(t) is applied to the end of the bar. Find the response 0(t) if force F(t)...
1 m Mm F Sl. In the mechanism shown the circular body with the mass moment of inertia I about 0. i.e. the center of gravity of the body, rotates about O. The T shaped body with the mass m is attached to that circular k body through the joint A such that OA = r. and it translates along the horizontal direction. The linear spring with stiffness k is placed between the T shaped body and the ground such...
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in this problem and where did I go wrong in solving this problem
3. A continuous force f 80 sin(t) N acts on Rack mi in the mechanical system shown below. Spring constant k 10 N/m, k- 30 N/m, mass mi 3kg, m2 4 kg, m3 5 kg, mass moment o inertia of the pinion Je 0.24 kg m2, Radius R-0.1 m, Radius R2 0.2 m, and...
A door shown in the figure) undergoes rotational motions about the vertical axis. The governing equation of rotational motion is given by Jyö + C70 + k 0 = 0 where Jo is the moment of inertia of the door, Ct is the rotational viscous damping and kt is the rotational stiffness of the door hinge. Assume that the door is 0.8 m wide (L = 0.8 m) and has a mass m of 15 kg. The moment of inertia...
A rigid bar with mass m and length L is pivoted at the fixed point O. A small disk of mass M is attached at the upper end of the bar. The disk is attached to a spring of stiffness k and a viscous damper with damping constant c. The moment of inertia of the bar about point O is Io M2/3 and the spring is unstretched when the bar is vertical. rs Under what condition is the vertical position...
I want matlab code.
585 i1 FIGURE P22.15 22.15 The motion of a damped spring-mass system (Fig. P22.15) is described by the following ordinary differ- ential equation: dx dx in dt2 dt where x displacement from equilibrium position (m), t time (s), m 20-kg mass, and c the damping coefficient (N s/m). The damping coefficient c takes on three values of 5 (underdamped), 40 (critically damped), and 200 (over- damped). The spring constant k-20 N/m. The initial ve- locity is...
. The system shown below consists of a homogeneous rigid rod with mass m, length l, and mass center of gravity G where the mass moment of inertia of the rod about G is given by: Translational spring with stiffness k supports the rod at point B, and rotational damper c, İs connected to the rod at its pivot point A as shown.ft) is an external force applied to the rod. Derive the equation of motion of the single degree...
PROBLEM -2 An Inertia J of radius r attached to a fixed axis of rotation A as shown below. The inertia is in contact with a mass M attached via aspring of stiffness K to a fixed wall. The inertla- mass contact is subject to viscous friction of coefficient f. The motion of the mass with respect to the horlzontal floor is subject to the same viscous friction coefficient f..The system input is a horizontal force f(t) on the mass...
2 with spring stiffness k 1000 N/m, Consider a mass-spring-damper system shown in Figure mass m = 10 kg, and damping constant c-150 N-s/m. If the initial displacement is xo-o and the initial velocity is 10 m/s (1) Find the damping ratio. (2) Is the system underdamped or overdamped? Why? (3) Calculate the damped natural frequency (4) Determine the free vibration response of the system.
Q1- For the system shown below, with small mass of value (m) and lever of mass moment of inertia (J). • find equivalent mass, equivalent stiffness, and equivalent damping, all these interms of (x) displacement . Get equation of motion Interms of these equivalent quantities. • Find natural frequency (Wn) and damping ratio (zeta). • Find X(t) when the system condition is critically damping ,,X(0)=M and v(0)=0. tinfring