Question

Java problem

In this problem, the first input is a positive integer called n that will represent the number of lines to process. The lines to be processed have one or more integers separated by whitespaces. For each of these lines, you must output:

The minimum value of the integers

The maximum value of the integers

The sum of the integers

It is worth to mention that the number of integers of each line is not known a priori and can varry from line to line. Write a program that solve this requirement.

Input Format

The first line contains n, the number of lines to be processed. The remaining n lines are the lines to be processed.

Constraints

n must be a positive integer.
The lines to be processed must have at least one integer.

Output Format

For each line to be processed, the output must be formed by 3 space-separated integers: min max sum
min: the minimum value of the integers of the line.
max: the maximum value of the integers of the line.
sum: the sum of the integers of the line.

Sample Input 0

4
-9 17 77 -18
55 0 42 11 7 90 -2 -15 30
-8 0 2
8 12 22 -1 5

Sample Output 0

-18 77 67
-15 90 218
-8 2 -6
-1 22 46

Answer 1

/*The whole answer is well commented so please create a class SumMinMax.java and copy whole answer and execute

*

*Here I will use BufferedReader to read input from console because it is fastest and

*best read lines from console but It reads lines in string format you need to process it

*

*So You can use Integer.parseInt(str) method to convert a string to integer

*str.split() method to split string

*

* So after reading input as string i will convert the string to integer of array then

* We can find min max easily in array of integer

*

* How to find min?

* Declare a variable min;

* assign arr[0] means first element of array to it min=arr[0]

* now iterate over array from index 1 to n-1 and check if(arr[i]<min) then

* modify the value of min as min=arr[i]

*

* ex- arr=[5,2,1]

* min=arr[0]=5

* if(arr[1]<min) => 2<5 => min=2

* if(arr[2]<min) => 2<1 => min=1

* So same procedure for max

*

*

* Sample Input:

4

-9 17 77 -18

55 0 42 11 7 90 -2 -15 30

-8 0 2

8 12 22 -1 5

*Sample Output:

-18 77 67

-15 90 218

-8 2 -6

-1 22 46

*If you are copy pasting input then press Enter to see last output

*/

import java.io.*;

import java.util.*;

public class SumMinMax {

public static void main(String[] args) throws IOException {

//Instantiating BufferedReader

BufferedReader br=new BufferedReader(new InputStreamReader(System.in));

//Now Reading n as it is single integer we can directly convert to integer

//ReadLine method reads a complete line from console

int n=Integer.parseInt(br.readLine());

//Below code of block will read n lines and find min -max -sum

for(int t=1;t<=n;t++)

{

//Below line will read a line and split it and will create array of Strings

String[] strs=br.readLine().split(" ");

//Finding number of elements in line

int len=strs.length;

//Creating integer array

int[] numbers=new int[len];

//Now Converting array of strings to array of integers

for(int i=0;i<len;i++)

{

numbers[i]=Integer.parseInt(strs[i]);

}

//Declaring min, max, sum variable

int min=numbers[0];

int max=numbers[0];

int sum=numbers[0];

for(int i=1;i<len;i++)

{

//Checking for min

if(numbers[i]<min)

min=numbers[i];

//Checking for max

if(numbers[i]>max)

max=numbers[i];

//Adding to sum

sum =sum +numbers[i];

}

//Printing out

System.out.println(min+" "+max+" "+sum);

}

}

}