The reaction 2 NO2(g) → 2 NO (g) + O2(g) has rate constants of 2.70 x 10-2 M-1s-1 at 227 oC and 0.240 M-1s-1 at 277oC. What is the activation energy of this reaction? (Given: Arrhenius equation, k = Ae-Ea/RT )
A) 99.6 kJ/mol
B) 22.8 kJ/mol
C) 49.8 kJ/mol
D) -22.8 kJ/mol
E) 65.3 kJ/mol
I'm unsure on how to do it since you're not given the frequency factor
The reaction 2 NO2(g) → 2 NO (g) + O2(g) has rate constants of 2.70 x...
The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 175 kJ/mol and the change in enthalpy for the reaction is ΔH = -375 kJ/mol . What is the activation energy for the reverse reaction?
The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 200 kJ/mol and the change in enthalpy for the reaction is ΔH = -200 kJ/mol . What is the activation energy for the reverse reaction?
The activation energy for the reaction NO2(g)+CO(g)⟶NO(g)+CO2(g) is Ea = 150 kJ/mol and the change in enthalpy for the reaction is ΔH = -375 kJ/mol . What is the activation energy for the reverse reaction?
(a) 2 NO2(g) à 2 NO(g) + O2(g) The rate law for this reaction is 2nd order. The rate constant is k = 0.775 M¯¹s¯¹. How much time would it require for [NO2] to go from 0.06M to 0.05M? (b) A 1st order reaction has a rate constant of k = 1.0 X 10¯³ s¯¹ at 25ᴼC. If the reaction rate doubles (2X faster) at 35ᴼC, what is the activation energy (Ea) for this reaction?
You have the following reaction: NO2 (g) + CO (g) ⟶ NO (g) + CO2 (g) The rate constant (k) at 701 K is 2.57 M-1s-1. If the activation energy is 150 kJ/mol, what is k at 895 K? R = 8.314 J/(mol*K) A) 680 M-1s-1 B) 443 M-1s-1 C) 2.58 M-1s-1 D) 0.950 M-1s-1 E) 6.52 M-1s-1
The rate of the reaction: CO (g) + NO2 (g) à CO2 (g) + NO (g) was measured at several temperatures, and the following data were collected: Temp (oC) K (M-1s-1) 35 0.184 45 0.322 Using this data determine the value of Ea (energy of activation)
The reaction 2NO2 → 2NO + O2 obeys the rate law: rate = 1.4 x 10-2[NO2]2 at 500 K . What would be the rate constant at 310 K if the activation energy is 80. kJ/mol? This is a second order reaction, giving k the units of M-1S-1 This will not change with the change in temperature. Do not include units in your answer. Exponential numbers need to be entered like this: 2 E-1 means 2 x 10-1. The rate...
There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation: k=Ae−Ea/RT, where k is the rate constant, A is the frequency factor, Ea is the activation energy, R=8.314 J mol−1 K−1 is the gas constant, and T is the absolute temperature. A certain...
There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation: k=Ae−Ea/RT, where k is the rate constant, A is the frequency factor, Ea is the activation energy, R=8.314 J mol−1 K−1 is the gas constant, and T is the absolute temperature. A certain...
The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...