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The reaction 2NO2 → 2NO + O2 obeys the rate law: rate = 1.4 x 10-2[NO2]2...

The reaction

2NO2 → 2NO + O2

obeys the rate law:

rate = 1.4 x 10-2[NO2]2 at 500 K .

What would be the rate constant at 310 K if the activation energy is 80. kJ/mol? This is a second order reaction, giving k the units of M-1S-1 This will not change with the change in temperature. Do not include units in your answer. Exponential numbers need to be entered like this: 2 E-1 means 2 x 10-1.

The rate constant, k, at 310 K equals:

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