1.50 g Na2HPO4 and 1.30 g NaH2PO4 are dissolved in water and brought to a final...

Question

Question

1.50 g Na2HPO4 and 1.30 g NaH2PO4 are dissolved in water and brought to a final volume of 100.0 mL

science chemistry

Answer 1

Answer #1

Mo nl 乂 1000 4.9Loo M. ),30 M二0.108 0 05 o 108 pH 6-8

Answer 2

Similar Homework Help Questions

a) What are the concentrations of Na2HPO4 and NaH2PO4 in a 0.30 M phosphate buffer solution...

a) What are the concentrations of Na2HPO4 and NaH2PO4 in a 0.30 M phosphate buffer solution pH 7.0? Use pKa 6.82 b) Describe how you would prepare 250 mL of the buffer in part (a) given that you have available to you a 1.0 M stock solution of NaH2PO4 and solid Na2HPO4(FW 141.96 g/mol). Provide your answer in milliliters of NaH2PO4 and grams of Na2HPO4. c) Suppose you use 100 ml of this buffer in an experiment and 0.003 mol...
1) Solution Components A 1 mL 100 mM NaH2PO4 + 9 mL 100 mM Na2HPO4 B...

1) Solution Components A 1 mL 100 mM NaH2PO4 + 9 mL 100 mM Na2HPO4 B 5 mL 100 mM NaH2PO4 + 5 mL 100 mM Na2HPO4 C 9 mL 100 mM NaH2PO4 + 1 mL 100 mM Na2HPO4 D 10 mL 100 mM NaH2PO4 stock solution E 10 mL 100 mM Na2HPO4 stock solution F 10 mL distilled water pKa of phosphate: 6.8 How would you calculate the pH of each equation using the Henderson Hasselbalch equations? 2) Tris...
What is the pH of the buffer that results when 14.0 g of NaH2PO4 and 7.84...

What is the pH of the buffer that results when 14.0 g of NaH2PO4 and 7.84 g of Na2HPO4 are diluted with water to a volume of 0.940 L? (K, of H2PO4 = 6.2E-8, the molar masses of NaH2PO4 and Na2HPO4 are 120.0 g/mol and 142.0 g/mol, respectively) 0 7.21 0 7.53 0 -6.88 O 6.96 O 6.88

What is the pH of the buffer that results when 10.0 g of NaH2PO4 and 15.0...

What is the pH of the buffer that results when 10.0 g of NaH2PO4 and 15.0 g of Na2HPO4 are diluted with water to a volume of 0.50 L? (Ka of H2PO4- = 6.2 × 10-8, the molar masses of NaH2PO4 and Na2HPO4 are 120.0 g/mol and 142.0 mol, respectively) a) 7.31 b) 7.21 c) 7.13 d) 8.05 e) 8.39 Answer is a. Please show calculations. I keep working on it and cant seem to get the right answer.
Calculate the pH of a buffer solution that contains 0.56 M NaH2PO4 and 0.21M Na2HPO4 Calculate...

Calculate the pH of a buffer solution that contains 0.56 M NaH2PO4 and 0.21M Na2HPO4 Calculate the change in pH if 0.050 g of solid NaOH is added to 200 mL of the solution in the problem above.
A buffer solution contains 0.235 M NaH2PO4 and 0.371 M Na2HPO4 If 0.0297 moles of nitric...

A buffer solution contains 0.235 M NaH2PO4 and 0.371 M Na2HPO4 If 0.0297 moles of nitric acid are added to 225 mL of this buffer, what is the pH of the resulting solution ? (Assume that the volume change does not change upon adding nitric acid pH =

What is the final temperature of the solution when 4.806 g of sodium hydroxide is dissolved in 100.0 mL of water at an i...

What is the final temperature of the solution when 4.806 g of sodium hydroxide is dissolved in 100.0 mL of water at an initial temperature of 24.5 C?. The density of water is 0.9969 g/cm3, and the heat capacity is 4.184 J/C. The enthalpy of dissolution for sodium hydroxide is -44.2 kJ/mol.
0.6573 g of potassium iodate is dissolved and diluted to a volume of 100.0 mL. Then...

0.6573 g of potassium iodate is dissolved and diluted to a volume of 100.0 mL. Then 25.00 mL of this stock solution is pipetted into a 100.0 mL volumetric flask which is filled to the mark with water. What is the concentration of the final standard solution in mol/L? Include units in your answer, and round the final answer to the correct number of significant figures.
What volumes of 0.1M Sodium phosphate monobasic (NaH2PO4), 0.1M sodium phosphate dibasic (Na2HPO4), and water would...

What volumes of 0.1M Sodium phosphate monobasic (NaH2PO4), 0.1M sodium phosphate dibasic (Na2HPO4), and water would you have to mix to make 100mL of a .05M Phosphate buffer at pH 7.4? pKa = 7.21

3. (hard) 85.0 g NaCl was dissolved in 1.50 L water. 765 mL of this solution...

3. (hard) 85.0 g NaCl was dissolved in 1.50 L water. 765 mL of this solution was heated on a hotplate 488 mL of water was evaporated off. What is the resulting concentration of the sodium chloride die beleid en die gelution? and then 7b] = D.7652 488 m > 1,438L