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What is the final temperature of the solution when 4.806 g of sodium hydroxide is dissolved in 100.0 mL of water at an i...

What is the final temperature of the solution when 4.806 g of sodium hydroxide is dissolved in 100.0 mL of water at an initial temperature of 24.5 C?. The density of water is 0.9969 g/cm3, and the heat capacity is 4.184 J/C. The enthalpy of dissolution for sodium hydroxide is -44.2 kJ/mol.

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Answer #1

q = ms\DeltaT

mass of solution = mass of water + mass of sodium hydroxide

                           = (100*0.9969) + 4.806

                           = 104.496 g

moles of NaOH = 4.806/40

                         = 0.12015 moles

1 mole of NaOH gives heat energy -------> 44.2 KJ

0.12015 moles of NaOH gives heat energy ----> (44.2*0.12015)/1

                                                                      = 5.31063 KJ

                                                                      = 5310.63 J

5310.63 = 104.496 * 4.184*(T2 - 24.5)

T2 = 36.65 0C

final temperature of the solution = 36.65 0C

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