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Sodium hydroxide (NaOH) has a lattice energy of -887 kJ/mol and a heat of hydration of...

Sodium hydroxide (NaOH) has a lattice energy of -887 kJ/mol and a heat of hydration of -932 kJ/mol.

Part A

How much solution could be heated to boiling by the heat evolved by the dissolution of 22.0 g of NaOH? (For the solution, assume a heat capacity of 4.0 J/g⋅∘C, an initial temperature of 25.0 ∘C, a boiling point of 100.0 ∘C, and a density of 1.05 g/mL.)

Express your answer using two significant figures.
V
=		 mL

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Answer #1

Heat evolution by dissolution of 1 mole NaOH

= Lattice energy - hydration energy

= (-887kJ/mol) - (-932kJ/mol)

= 45kJ/mol

(Molar mass of NaOH = 39.997g/mol)

using the formula

Density = mass/volume

And

Volume = mass/density

Mass = 82.5g

density of solution = 1.05g/mL

So

Volume = (82.5g)/(1.05g/mL)

Volume = 78.57mL

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