Solution:
3.4.1 AND 3.4.2
AS CAN BE CONCLUDED FROM TABLE 5....FOR FIRST AND THE LAST COMBINATION THE INPUTS ARE SAME AND THE LED GLOWS
BINARY INPUTS IN THE ORDER A3 A2 A1 A0 B3 B2 B1 B0
0000 0000

0010 0011

0111 0110

1100 0100

1101 1110

1110 1110

TABLE 5

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PART 3.5.1 AND 3.5.2
OUTPUTS
X3 X2 X1 X0 FOR
D1 = 0 AND
A3 A2 A1 A0 = 0000

A3 A2 A1 A0 = 0010

A3 A2 A1 A0 = 0111

A3 A2 A1 A0 = 1100

A3 A2 A1 A0 = 1101

A3 A2 A1 A0 = 1110

OUTPUTS
X3 X2 X1 X0 FOR
D1 = 1 AND
A3 A2 A1 A0 = 0000

A3 A2 A1 A0 = 0010

A3 A2 A1 A0 = 0111

A3 A2 A1 A0 = 1100

A3 A2 A1 A0 = 1101

A3 A2 A1 A0 = 1110

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PART 3.6


3.4.1 Build and simulate the comparator circuit shown in Figure 3, in Multisim. The inputs A3,...
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