Question

Part A A 2 20 kg block on a horizontal floor is attached to a horizontal spring that is initally compressed 0 0360 m. The spring has force constant 885 N/m. The coefficient of kinetic friction between the foor and the block is 0 35. The block and spring are released from rest and the block slides along the floor What is the speed of the block when it has moved a distance of 0.0100 m from its intiail position? (At this point the spring is compressed 0.0260 m ) im Previous Answers Request Answer X Incorrect Try Again; 5 attempts remaining Fio 12

Answer 1

Using conservation of energy

Workdone by spring - workdone by frictional energy = change in kientic energy of system

0.5 k ( x1^2 - x2^2) - u mg d = 0.5 m v^2

0.5 * 885 * ( 0.036^2 - 0.025^2) - 0.35* 2.2* 9.8* 0.01 = 0.5 *2.2* v^2

v = 0.4487 m/s

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