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Having issues? See our FAQ Guide QUESTION 1 1. Required Pin Diameter for a Frame The frame shown supports a mass of 500 kg. D

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mass, M = sooka W = mg = 500x9.81-4905 N FS-3 21 zum С. 13 Call = 150 MPa zu sooky PIN A Single Shear w for Member BD ŹM₂=0 aResultant force at Pin A FA = √(AM²+ (Ayz = [(-2w1²+ (-w)2 = wis FA = Wis Maximum shear stress in pin at A, Tman = FA A Iman

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