Question

Your answer is partially correct. Try again. Under standard conditions, will the following reaction proceed spontaneously as written? Cyto a (Fe2+) + cyto b (Fe3+) = cyto a (Fe7+) + cyto b (Fe2+) In order to determine this, the equation 4 e acceptor) A donor) is applied. In this case the electron acceptor is | Cytochrome b (Fe3+) and the Vand the electron donor is Il Cytochrome a (Fe2+) isCytochrome a (F22+) | , so the value for AE" is +1 v. Because J v. Because this number is ll less than zero Il greater than zero J and the reaction will spontaneously proceed in the I opposite direction from that written Al exact number, no tolerance

Answer 1

Solo- Here all the blanks ane filled connectly exceft Cyto a Cfe?")+ cytob(Fes+t)== cytoalFe3t) + Cyto b ( Fe24) Now: Oxidafion: cyto a( Fe2) = Cyto a ( Fe3+) te CAnrde) Reduction: Cyt b (Fe3t) +e= Cyto b (Fe?t) cath ode) Soj Ecel= E° ca thode -E'anode E'afhee = Standand uneduction bokential of cafthede E'ande = Standasd vredluchion polantial of anade Ecell = 0:077v- 0-29V 7E'ceya-0-113 v