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A sample of size n=96 is drawn from a normal population whose standard deviation is 5.7....

A sample of size n=96 is drawn from a normal population whose standard deviation is 5.7. The sample mean is 41.68. Construct a 99.9% confidence interval for m.

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Answer #1

Standard error of the mean = SEM = S/?N = 0.582

t(?, N-1) = 3.396

Confidence interval = m +/- (t(?, N-1)*SEM)

Mean = 41.68

Lower bound: 39.7

Upper bound: 43.66

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