Given that mean is 0.839
While two points are 0.703 and 0.975 respectively both are equidistant from the mean so as SD is not showing here so it's possible that these two points are 1SD away from mean or 2 SD away from mean or 3SD away from mean
As difference between points and mean is 0.975-0.839=0.839-0.136=0.136
Let if SD =0.136
Then points are "mean P/M 1 SD" then required % is 68%
While if SD=0.136/2=0.68
Then points are "mean P/M 2 SD " then required % is 95%
Where P/M means plus minus
As you have hidden the value of SD so match the SD with two SDs given here and depend on that one of above 2 answers is correct answer of your question.
(c) Use the Empirical Rule to determine the percentage of candies with weights between 0.703 and...
The data to the right represent the weights (in grams) of a random sample of 50 candies. Complete parts (a) through (f). 0.89 0.85 0.91 0.95 0.75 0.85 0.86 0.75 0.82 0.98 0.86 0.79 0.77 0.75 0.71 0.83 0.82 0.92 0.77 0.73 0.82 0.84 0.82 0.83 0.85 0.87 0.81 0.92 0.77 0.82 0.99 0.73 0.89 0.86 0.87 0.83 0.82 0.85 0.87 0.93 0.82 0.74 0.84 0.89 0.93 0.92 0.84 0.77 0.79 0.83 (a) Determine the sample standard deviation weight gram(s)...
The data to the right represent the weights (in grams) of a random sample of 50 candies. 0.82 0.83 0.91 0.99 0.71 0.87 0.88 0.76 0.85 0.98 0.87 0.79 0.78 0.77 0.73 0.85 0.89 0.94 0.78 0.75 0.82 0.98 0.81 0.83 0.81 0.89 0.81 0.91 0.78 0.81 0.98 0.72 0.88 0.82 0.89 0.84 0.84 0.89 0.88 0.94 0.81 0.71 0.84 0.85 0.94 0.85 0.82 0.77 0.76 0.84 Complete parts (a) through (f). (a) Determine the sample standard deviation weight. grams)...
I need help with the final part - (f) Determine the actual percentage of candies that weigh more than 0.91 gram. - Thank you! The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86 0.79 0.73...
I need help at the bottom with - (d) Determine the actual percentage of candies that weigh between 0.7 and 0.98 gram, inclusive - Thank you! The following data represent the weights (in grams) of a random sample of 50 candies. 0.85 0.89 0.82 0.81 0.85 0.87 0.96 0.89 0.91 0.91 0.81 0.86 0.77 0.89 0.85 0.84 0.75 0.84 0.71 0.84 0.91 0.76 0.77 0.95 0.83 0.91 0.88 0.85 0.83 0.78 0.97 0.84 0.75 0.75 0.81 0.76 0.86 0.87 0.86...
The following data represent the weights (in grams) of a random sample of 50 candies. 0.82 0.81 0.91 0.95 0.74 0.89 0.87 0.75 0.81 0.95 0.88 0.78 0.76 0.75 0.71 0.84 0.87 0.91 0.75 0.75 0.85 0.96 0.85 0.81 0.83 0.88 0.83 0.94 0.76 0.83 0.97 0.71 0.85 0.81 0.85 0.81 0.83 0.86 0.86 0.91 0.82 0.71 0.83 0.86 0.92 0.82 0.82 0.78 0.77 0.81 (a) Determine the sample standard deviation weight. s= 0.07 gram (Round to two decimal places...
I need help with question (d)
T 0.82 The following data represent the weights (in grams) of a random sample of 50 candies. 0.89 0.87 0.87 0.84 0.95 0.81 0.94 0.97 0.75 0.76 0.75 0.78 0.84 0.85 0.82 0.92 0.78 0.72 0.83 0.81 0.82 0.82 0.82 0.87 0.81 0.91 0.78 0.81 0.96 0.72 0.86 0.84 0.86 0.94 0.74 0.82 0.87 0.92 0.89 0.86 0.91 0.85 0.84 0.79 0.77 0.81 0.78 0.87 0.74 (a) Determine the sample standard deviation weight. S=...
standard deviation of 50 grams. Use the empirical rule to determine the following. The weight of an organ in adult males has a bell-shaped distribution with a mean of 320 grams and (a) About 99.7% of organs will be between what weights? (b) What percentage of organs weighs between 270 grams and 370 grams? (c) What percentage of organs weighs less than 270 grams or more than 370 grams? (d) What percentage of organs weighs between 170 grams and 420...
Please answer each of the parts in the following question. Show
all steps. Thanks in advance!
The following data represent the weights (in grams) of a random sample of 50 candies. 0.86 0.84 0.93 0.99 0.73 0.85 0.87 0.77 0.82 0.83 0.82 0.78 0.76 10.75 0.75 0.84 0.86 0.93 0.77 0.74 0.83 0.99 0.83 0.83 0.85 0.86 0.81 0.95 0.79 0.83 0.96 0.75 0.88 0.86 0.88 0.85 0.82 0.87 0.86 0.91 0.87 0.74 0.83 0.85 0.93 0.87 0.84 0.74 0.77...
i need help with with c and d. im using the T1-84 calculator
for my class. thank you
X23. The Empirical Rule The following data represent the weights (in grams) of a random sample of 50 M&M plain candies. 0.87 0.88 0.82 0.90 0.90 0.84 0.84 0.91 0.94 0.86 0.86 0.86 0.88 0.87 0.89 0.91 0.86 0.87 0.93 0.88 0.83 0.95 0.87 0.93 0.91 0.85 0.91 0.91 0.86 0.89 0.87 0.84 0.88 0.88 0.89 0.79 0.82 0.83 0.90 0.88 0.84...
Please help answer questions (a)-(c).
Objective 4: Use the Empirical Rule to Describe Data That Are Bell-Shaped 3.2 Measures of Dispersion 3.2.29 0 of 1 Point Scores of an IQ test have a bell-shaped distribution with a mean of 100 and a standard deviation of 11. Use the empirical rule to determine thefollowing (a) What percentage of people has an IQ score between 67 and 133? (b) What percentage of people has an IQ score less than 67 or greater...