Question

1. Here you have a saturated solution a. Calculate the molar solubility of cadmium (I)hy b. (extra credit) What is the pH of this solution? c. What would be the molar solubility of cadmium () () on of cadmium (ID hydroxide, Cd(OH)2 at 25 oC. (1.5 pts) sodiumn byodar solebiliy of yxide when the solution nitily contains 0.010 M of sodium hydroxide (NaOH)? d. um (lI) hydroxideicther the following chemicals can increase or decrease the solubility of cadmium (II) hydroxide. Explain your answers. HCl Ca(OH)2 CdClz H20 . 1-L buffer solution is prepared using 0.150 M of hypobromous acid (HBrO) and 0.200 M of sodium hypobromite (NaBrO). (1.5 pt) a. Calculate the pH of this buffer solution. (K, of hypobromous acid (HBrO) is 2.810) b. If 1.00 ml of 5.00 M NaOH was added to this buffer solution, how would the pH of the buffer solution change? Show your calculation to find the pH. 3. 100 mL of 0.100 M lactic acid (HCjH,O) is titrated with 0.100 M of potassium hydroxide (KOH) solution (Ka of lactic acid is 1.4 x 10". (1.5 pt) a. Calculate the pHl of the solution when 45 ml. of potassium hydroxide is added to the lactic acid solution. Calculate the pH of the solution at the equivalence point. following indicators would be the best indicator for this titration? Explain b. (extra credit) Which of the e. your answer Indicator pH range of color pH range of color Indicator change 6.0-7.6 6.8-8.3 9.4-10.6 change 1.2-2.8Bromothymol blue Thymol blue Bromocresol green Litmus Phenol red 5.0-8.0 Thymolphthalein

Answer 1

Let 's'be the molay Co (OH 2.S -12. -12 v 4 MotaY Solubilst1-6.30 x105 M. b) ( = 2s = 2x 6.30 x105-12-6x10 6.30 X 105M- = 5 1001. = decreas ed due to tra common on oH) ca (oH) 2 CS) '04 s l. Oxiol 2- Sx@of = ksp = = 1.0x108 n lo Hcl H reach with OH to form weakly dissocinlad Ho. A As the oA) decreckes, equihibriun will shitt Le-chatehes brin cd@i)2 아 Fnu resses ushen He is added

As cd" increases urnn's ep uitib rium will shitt to ft Common on eftect) and solubi ity decreases Solution becomes uns atahated, e ern shi怓tought (or) selubi lit increases Са (он) provides OH ions . Hene due to common ion etect, colubikit decr eses d) 2. Sa It) an acianc 9) pka=-log kaニー뼘 @s x1-9)-855 8.55 + 0-1249 = 8.67 PH = 8.ss + log (o.200 M №매 is added, 얘 reacts with acidic couponent b) When at lhe batterEtero) to produce Na Bro (salt). Henue PH Will mcrease enie 0.005 moles = 0-150 M x1L = O. Iso moles Moles of (HBYO) Molec ot (Na Bro) O.20o moles 6.200 +0. 005 o 20s O.005 士 0-150 E o.145 log ( -) O 205 moles of NABYD =8.55 + = pica + log = 8.55 +0.150 pH Moles of H8ro 8.70