Let 'x' is the % abundance for 115.3026 amu.
Then (100-x) will be abundance of 122.8251 amu.
Now,
115.3026*x + 122.8251*(100-x) / 100 = 118.1471
115.3026x + 12282.51 - 122.8251x = 11814.71
7.5225x = 467.8
x = 62.19 % .... Answer
If the mass of the only two isotopes of an element are 115.3026 amu and 122.8251...
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