Homework Answers
H2PtCl6 + 2 NH4+ -------------> (NH4)2PtCl6 + 2 H+
(NH4)2PtCl6 ---------------> Pt (s) + 2 Cl2 (g) + 2 NH3 (g) + 2 HCl (g)
mass of Pt = 0.5881 g
moles of Pt = 0.5881 / 195.084
= 3.0146 x 10^-3 mol
moles of NH3 = 2 x moles of pt
= 2 x 3.0146 x 10^-3
= 6.029 x 10^-3 mol
mass of NH3 = 6.029 x 10^-3 x 17
= 0.1027 g
mass % of NH3 = (0.1027/ 0.2213) x 100
= 46.4 %
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