You and your roommate plot to drop water balloons on students entering your dorm. Your window is 30m above the sidewalk. You plan to place an X on the sidewalk to mark the spot a student must be when you drop the balloon. You note that most students approach the dorm at about 3m/s .
How far from the impact point do you place the X?
In this answer figures have been changed, but this may help you.
Height of room abovesidewalk = 65ft = 65 *0.3048 m
h = 19.81 m
By second equation ofmotion
h = u* t + (1/2) * g * t2
u = 0 asthe balloon are dropped. Hence
19.81 = *t + 0.5 * 9.8 * t2
t = ?4.04 = 2.01 s
In this time the student onsidewalk must walk the distance 'd' between Xmark and impact point.
d = v *t = 1.7 *2.01 = 3.42 m
So the mark would be made at 3.42 m fromimpact point
s=ut+1/2at2
for falling ballon
s=30m and u=0
so time required for it to come down
30=0+1/2 x9.8 t2
t=2.47S
since they are moving with velocity 3m/s
position x=vt=3x2.47=7.42m away from window
You and your roommate plot to drop water balloons on students entering your dorm. Your window...
Constants| Periodic Table Part A You and your roommate plot to drop water balloons on students entering your dorm. Your window is 30 m above the sidewalk. You plan to place an X on the sidewalk to mark the spot a student must be when you drop the balloon. You note that most students approach the dorm at about 1 m/s. How far from the impact point do you place the X? Express your answer to one significant figure and...
the
concentration is .1000 M for NaOH. you cN disregard the second
column. but there is no further information.
equivalence point is 22.95. i dont have mL NaOH
this is all i have
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