Question

2. (4 marks) Write a C function to find the average of all array elements in an one-dimensional array. The function prototype is as follows, float array_average(float a[], int n); /* find the average of all array elements in array a, and n is the size of array a.

Answer 1

Here I am providing the code and the output for the given problem

Code

#include <stdio.h> float array_average(float a[], int n); //function declaration float array_average(float a[], int n){ //function definition int i; float sum = 0; //initialising the variables for(i 0; i<n; i++) sum+=a[i]; //adding all the elements in the array return sum/n; //returning the average of array } int main() int n = 9; float a[9] = {1,2,3,4,5,6,7,8,9}; //declaring one dimensional array float result = array_average(a,n); // calling function array_average printf("The average of the array is %.2f",result); //displaying the result }

Output

The average of the array is 5.00

Code

#include <stdio.h>

float array_average(float a[] , int n); //function declaration

float array_average(float a[] , int n){ //function definition
  
int i;
  
float sum = 0; //initialising the variables
  
for(i = 0 ; i < n ; i++) //adding all the elements in the array
sum+=a[i];
  
return sum/n; //returning the average of array
  
  
}

int main()
{
int n = 9;
  
float a[9] = {1,2,3,4,5,6,7,8,9}; //declaring one dimensional array
  
  
float result = array_average(a,n); //calling function array_average
  
printf("The average of the array is %.2f",result); //displaying the result

  
}

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