Question

c++, need help thank you

Given an array of ints, return the sum of all elements from the array that come before the first element that equals number 4 in the array. The array will contain at least one 4. Function prototype: int pre4int array ( ], int size); Hint: to find the array size, use: int size = sizeof(array) / sizeof( array[0]); Sample runs: int array1[ ] = {1, 2, 4, 1); pre4(array1, 4); // returns 3 int array2 [ ] = {2, 1, 2,4}; pre4(array2, 4); // returns 5 int array3[] = {2, 4, 2,5}; pre4(array3, 4); // returns 2 int array4[ ] = {4, 2,5}; pre4(array4, 3); // returns 0

Answer 1

int pre4(int array[], int size){
    int sum = 0;
    for(int i = 0;i<size;i++){
        if(array[i]==4){
            return sum;
        }
        sum += array[i];
    }
    return sum;
}