Question 22.5 pts
Gallium consists of two isotopes of masses 68.95 amu and 70.95 amu with abundances of 60.16% and 39.84%, respectively. What is the average atomic mass of gallium?
| 69.95 |
| 71.95 |
| 70.15 |
| 69.75 |
average atomic mass = sum of individual isotope mass x relative abundance.
average atomic mass = (68.95 x 60.16 / 100) + (70.95 x 39.84 / 100)
average atomic mass = 41.48 + 28.27
average atomic mass = 69.75
answer = 69.75
Question 22.5 pts Gallium consists of two isotopes of masses 68.95 amu and 70.95 amu with...
The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu. The relative abundances of these three isotopes are 99.76, 0.03800, and 0.2000 percent, respectively. From these data calculate the average atomic mass of Oxygen (in amu).
the average atomic mass of gallium is 69.72 amu. the important isotopes of gallium are 69Ga (68.92 amu) and 71Ga (70.92 amu). which isotope of gallium is more abundant? explain your reasoning. And what is the percent composition of each isotope of gallium?
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 75% and 25%, respectively. Calculate its average atomic mass.
QUESTION 3 A fictitious element is composed of isotopes A and B with masses of 61.9887 and 64.9846 amu respectively. The average atomic mass of the element is 64.52 amu. What can you conclude about the natural abundances of the two isotopes? O The natural abundance of isotope A must be greater than that of isotope B OThe natural abundance of isotope B must be greater than that of isotope A. O The natural abundances of both isotopes must be...
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 125 amu and 127 amu, with natural abundances of 80% and 20%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place. -------- amu
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu
5. An element consists of two isotopes in the indicated natural abundances: Isotope A, mass=84.9118 amu, abundance = 72.15% Isotope B, mass = 86.9092 amu, abundance = 27.85% What is the atomic weight of this element? What is the identity of the element? Show your calculations.
Li are 6.0151 amu and 7.0160 amu, respectively. Calculate the 1. The atomic masses of Li and natural abundances of these two Dimethyl sulfoxide [(CHs)2SO], also called DMSO, is an important solvent that penetrates the isotopes. The average atomic mass of Li is 6.941 amu. 2. skin, enabling it to be used as a O atoms in 7.14 x 103 g of dimethyl sulfoxide. topical drug-delivery agent. Calculate the number of C, S, H and
1. An unknown element has 3 isotopes with masses and abundances of 29.56 amu at 30%, 31.61 at 60%, and 33.19 at 10%. what is the average atomic mass based on this information? 2. what is the wavelength of a wave in meters if the frequency is 3.51 x 10^7 s-1 ?