Question

A steam era no 09 tle steam at- i a? °C Ass aeud irn ne msk

Answer 1

(a) The efficiency of the engine will be

$\eta=1-\frac{T_c}{T_h}=1-\frac{127+273}{427+273}=1-\frac{400}{700}=\frac{300}{700}=0.4286$

(b) Output work will be

$W=\eta Q=0.4286\times2000=857.143$ J$$

(c) Energy exhausted will be

$Q'=Q-W=Q-\eta Q=2000-857.143=1142.857$ J$$

(d) Let the temperature of hot steam be $T_h'$ then

$2\eta=1-\frac{T_c}{T_h'}\Rightarrow 0.4286\times2=1-\frac{400}{T_h'}\Rightarrow \frac{400}{T_h'}=0.143\\ T_h'=\frac{400}{0.143} =2797.2^o$ K$=2797.2-273=2524.2^0$ C$$