no of moles = mass / molar mass
for C6H6 = 78 g / 78.11 g/mol => 0.99859 moles
C6H6 + 3 H2 -----------------------> C6H12
from the equation
1 mol C6H6 ----------------> 1 mol C6H12
0.99859 mol ------------------->?
=> 0.99859 * 1 / 1
=> 0.99859 moles
theoretical yield = 0.99859 mol * 84.16 g/mol => 84.0414 grams
percent yield = actual yield / theoretical yield * 100
percent yield = 42 / 84.0414 * 100 => 49.975 %
answer => c ) 50%
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