Question

Below is a table of results of E. coli grown in in nutrient broth (NB) and minimal medium (MM) over 220 min.

Time (min)	A600 of
	NB	MM
0	0.044	0.038
20	0.177	0.074
40	0.321	0.116
60	0.429	0.167
80	0.523	0.235
100	0.638	0.285
120	0.849	0.300
140	0.925	0.367
160	1.101	0.428
180	1.159	0.468
200	1.198	0.471
220	1.209	0.488

Using the above data, plot absorbance (log scale) versus time (linear), drawing both conditions on one set of axes.

Upload the graph as a jpg file to this assignment (an Excel graph or a photo of a manually drawn graph is acceptable).

Label your graph appropriately.

Remember, you will not get any marks if your semi-log graph is titled as "Absorbance versus time" because this is already the label of your Y and X axes.

Determine the growth rate constant for E. coli growing for each culture media. Show your calculations in the space below.

Answer 1

10 1 C 50 1g 15日 200 250 01 0.01

Blue- culture media 1, orange - culture media 2

culture media 1

growth rate constant (µ) = ( (log10 N - log10 N0) 2.303) / (t - t0)

= (0.321- 0.044) 2.303 /40 min

= 0.01594 min-1

culture media 2

growth rate constant (µ) = ( (log10 N - log10 N0) 2.303) / (t - t0)

= (0.523- 0.038) 2.303 /80 min

= 0.01396 min-1