Solution-
Successive discounts are
D1 = 25% = 25÷100 = 0.25
D2 = 15% = 15÷100 = 0.15
D3 = 10% = 10÷100 = 0.10
Now single discount equivalent to these three successive discounts is
D = {1-(1-D1)(1-D2)(1-D3)}
D = {1-(1-0.25)(1-0.15)(1-0.10)}
D = {1-(0.75×0.85×0.90)}
D = 0.42625
Hence single discount = 0.42625×100
= 42.625%
List Price = $ 2200
Hence the trade discount = 42.625% of $2200
= 0.42625×2200
= $937.75
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