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A 0.80 kg block of aluminum is heated at atmospheric pressure so that its temperature increases from 22.0°C to 40.0°C. (a) Find the work done on the aluminum. mJ (b) Find the energy added to it by heat. kJ (c) Find the change in its internal energy. kJ

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Answer #1

Work done on aluminium = energy added to aluminium = Change in internal energy of aluminium

E = MC_p\Delta T Here, Cp is specific heat of aluminium.

E = 0.80*0.91KJ*(40-22) = 13104 J

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