Question

u=0 here 5. Statics and Rotating Systems for 10 Points: Statics: A house painter with a mass of 90kg has a 10 kg 4m long ladder that has a roller at the top end so it won't scrape the house. This means there is no friction on the top of the ladder. He sets the ladder at an angle of 60°, and stands 3m up from the bottom of the ladder. (a) Draw a Free Body Diagram of just the Ladder. (b) Find the force of the wall acting on the top of the ladder. 60° Friction here

Answer 1

solution a um 3m "googl long. now, FOB.D NY, gokg b ) jo long now, since the ball is in equilibrium son Torque around o 2 =) 10 x( ) Colboº +9013 Cos 60 N₂ Lsimbo"=0 3 Na (G snooo) 1 Cod 60° + 50 x3cos 60° A₂ 10 + 135 (4 singol i, NE 10 X 41.85 Ml Hence, force of the wall on the top of the ladder = 41.854