For the reaction, PCl5 (g) <--> PCl3 (g) + Cl2 (g), Kc=33.3 at 760.0 C. In a container at equilibrium, there are 1.29 x 10-3 mol/L of PCl5 and 1.87 x 10-1 mol/L of Cl2.
Calculate the [PCl3] in the container.
Kc = [Cl2][PCl3] / [PCl5]
[Cl2] = 1.87 x 10-1 M
[PCl5] = 1.29 x 10-3 M
[PCl3] = ?
Kc = 33.3
33.3 = [0.187][PCl3] / [0.00129]
0.0429 = [PCl3] x 0.187
[PCl3] = 0.229 M = 2.29 x 10-1 M
For the reaction, PCl5 (g) <--> PCl3 (g) + Cl2 (g), Kc=33.3 at 760.0 C. In...
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