Question

Pt(s) + Fe2+ (aq) - P+2+ (aq) + Fe(s) [Fe2+] = 0.0083 M [P+2+] = 0.030 M The cell is not spontaneous. O spontaneous. Cu(s) +
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Pratears & Fels) Pris) & Fertag) Anodic half Reactions cathodic hay Deactius Pris) Pet 9 Fe castle [agithe - Fels) EanodetrenE cell = 0.Bov- 0.34v=0.46v cuis cu2te2le 290 tag + 2 ) 245 (5) f c4 + ASS) cac + 2ASES recall cel React Curs) + 2A n=2 no of

Add a comment
Know the answer?
Add Answer to:
Pt(s) + Fe2+ (aq) - P+2+ (aq) + Fe(s) [Fe2+] = 0.0083 M [P+2+] = 0.030...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 7 of 16 > Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentr...

    Question 7 of 16 > Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E ). Pt(s) + Fe2+ (aq) = P22+ (aq) + Fe(s) [Fe2+] = 0.0017 M [P12+] = 0.040 M The cell is O spontaneous. O not spontaneous Cu(s) + 2 Ag+ (aq) = Cu2+(aq) + 2 Ag(s) [Cu2+] =...

  • Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations...

    Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E Pt(s)Fe2+(aq) Pt2+(aq) + Fe(s) [Fe2+ [Pt2+] = 0.0023 M = 0.011 M The cell is V E = O not spontaneous. O spontaneous Cu(s)2 Ag (aq) Cu2+(aq) + 2 Ag(s) [Cu2+0.031 M [Ag*] = 0.031 M The cell is V E = O...

  • Calculate the cell potential, ? , for the given reactions at 25.00 °C using the ion...

    Calculate the cell potential, ? , for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (?∘red) . Pt(s)+Fe2+(aq)↽−−⇀Pt2+(aq)+Fe(s) [Fe2+]=0.0045 M[Pt2+]=0.022 M ?= V The cell is spontaneous. not spontaneous. Cu(s)+2Ag+(aq)↽−−⇀Cu2+(aq)+2Ag(s) [Cu2+]=0.013 M[Ag+]=0.013 M ?= V The cell is spontaneous. not spontaneous. Co2+(aq)+Ti3+(aq)↽−−⇀Co3+(aq)+Ti2+(aq) [Co2+] = 0.055 M[Co3+] = 0.020 M [Ti3+] = 0.0055 M[Ti2+] = 0.0090 M ?= V...

  • 26. Determine the redox reaction represented by the following cell notation. Fe(s) I Fe2+(aq) I| Cu2+(aq)...

    26. Determine the redox reaction represented by the following cell notation. Fe(s) I Fe2+(aq) I| Cu2+(aq) I Cu(s) A) Cu(s) + Fe2+(aq) B) Fe(s)+Cu2+(aq) Cu(s)+ Fe2+(aq) C) 2 Fe(s)+ Cu2+(aq)Cu(s) + 2 Fe2+(aq) D) 2 Cu(s) + Fe2+(aq)Fe(s)+ 2 Cu2+(aq) E) 3 Fe(s) + 2 Cu2+(aq) 2 Cu(s)+3 Fe2+(aq) Fe(s) + Cu2+(aq)

  • Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations...

    Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. QUESTION 1) Pt(s)+Fe2+(aq)−⇀↽−Pt2+(aq)+Fe(s) [Fe2+]=0.0013 M[Pt2+]=0.048 M E= ____ V? The cell is not spontaneous or spontaneous. QUESTION 2) Cu(s)+2Ag+(aq)−⇀↽−Cu2+(aq)+2Ag(s) [Cu2+]=0.017 M [Ag+]=0.017 M E= ____ V? The cell is not spontaneous or spontaneous. QUESTION 3) Co2+(aq)+Ti3+(aq)−⇀↽−Co3+(aq)+Ti2+(aq) [Co2+] = 0.065 M [Co3+] = 0.025 M [Ti3+] = 0.0060 M [Ti2+] = 0.0118 M...

  • For the electrochemical cell, Fe(s)| Fe2+ (aq)|| Cu2+ (aq)| Cu+ (aq) | Pt(s), determine the equlibrium...

    For the electrochemical cell, Fe(s)| Fe2+ (aq)|| Cu2+ (aq)| Cu+ (aq) | Pt(s), determine the equlibrium constant (Keq) at 25°C for the reaction that occurs.

  • Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations...

    Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E Pt(s) Fe2+(aq) Pt2+(aq) + Fe(s) Fe2+0.0050 M Pt2+10.035 M The cell is E = V not spontaneous O spontaneous. Cu(s)2 Ag(aq) Cu2t(aq) + 2 Ag(s) [Cu2+0.015 M [Ag 0.015 M The cell is E = V O spontaneous. O not spontaneous Co2+(aq)Ti3(aq)Co3t(aq) +...

  • Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s)...

    Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С

  • question iii 10. An electrochemical cell consists of a standard Fe/Fe electrode (Fe (aq) (1.OM) IFe...

    question iii 10. An electrochemical cell consists of a standard Fe/Fe electrode (Fe (aq) (1.OM) IFe (aq) (1.0M) IPt(s) and a copper metal electrode ( concentrations) Cu2 (aq) +2e Cu(s) Fe (aq) le Fe (aq) +0.34 V -034 +0.77V Mark what is the corect balanced equation for the spontaneous reac u (aq) Fe (aq) Cu(s)+Fe2 (aq) C) Cu(s) + Fe (aq) Cu (aq) + Fe (aq) α Cu2+(aq) + 2e → Cu(s) + Fe2+(aq) Cu → Cu2ト+20 94 i) (...

  • 1- Consider the following redox reaction: Fe(s) + Cu2+(aq) --> Fe2+(aq) + Cu(s)    EoCell =...

    1- Consider the following redox reaction: Fe(s) + Cu2+(aq) --> Fe2+(aq) + Cu(s)    EoCell = 0.78 V If [Cu2+] = 0.3 M, what [Fe2+] is needed so that Ecell = 0.76 V 2- Calculate the Eocell for the following redox reaction: Cu(s) + 2Ag+(aq) --> Cu2+(aq) + 2Ag(s)

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT