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Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine iCo2+(aq)Ti3+ (aq) Co3+(aq) + Ti2+(aq) [Co2+] [Co3+1 0.070 M = 0.025 M - Ti2+ [Ti3+] 0.0110 M = 0.0060 M The cell is E = V O s

Calculate the cell potential, E, for the given reactions at 25.00 °C using the ion concentrations provided. Then, determine if the cells are spontaneous or nonspontaneous as written. Refer to the table of standard reduction potentials (E Pt(s)Fe2+(aq) Pt2+(aq) + Fe(s) [Fe2+ [Pt2+] = 0.0023 M = 0.011 M The cell is V E = O not spontaneous. O spontaneous Cu(s)2 Ag (aq) Cu2+(aq) + 2 Ag(s) [Cu2+0.031 M [Ag*] = 0.031 M The cell is V E = O not spontaneous. O spontaneous
Co2+(aq)Ti3+ (aq) Co3+(aq) + Ti2+(aq) [Co2+] [Co3+1 0.070 M = 0.025 M - Ti2+ [Ti3+] 0.0110 M = 0.0060 M The cell is E = V O spontaneous not spontaneous
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Ianous we E = E O.o592 to9 nE no. elettrand E - Fe 16 3V. O.0Sa2 log [fet E = -1-63- 2 O.ol1 0.0592 loq -1-63 O.0023 2 <O 1.6

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