Question

4. (1 supporting cable when the cable is (a) moving with an upward acceleration of 2 m/s2 Opts) An elevator cab and its load have a combined mass of 1500 kg. Find the tension in the (b)not moving at all (c)moving with an upward constant velocity 2m/s (d) falling freely

Answer 1

Mass of the elevator cab is m = 1500 kg Free body diagram of elevator cab a = 2 m/s^2 where T be the tension in the supporting cable from Newton's second law T - mg = ma T - 1500 times 9.8 = 1500 times 2 T = 3000 + 14700 T = 17700 Newton when the cab is not moving then net force on the cab will be zero \r\n free body diagram of the cab is From Newton's second law T = mg T = 1500 times 9.8 T = 14700 Newton when the cab will move with constant velocity than from Newton's second law acceleration of the cab will be zero that is net force on the cab is zero. T = mg T = 1500 times 9.8 T = 14700 Newton \r\n Elevator cab falling freely means its acceleration will be equal to gravitational acceleration. From Newton's second law mg - T = mg T = mg - mg T = 0