Question
I need help to understand the increment of Brownian motion. Especially for second equation, why E[B(t+u)-B(t)^2] = u?
Please explain the details as much as possible. Thank you
math.ucsd.edu Ex. 8.1.4. Let us begin by observing some general consequences of the independence of the 2/3 213 crements of the Brownian motion. Suppose that Z is a random variable that depends only on the Brownian motion at several times t1, t,.,tn, all at most t. Then Z is independent of B(t u) -B(t) for u > 0, so EZ-B(t)], the second equality following from the independent increments and the third from the fact that E[B(t + u)] = E[B(t)) = 0. Likewise, with Z as before Finally, the same reasoning together with the fact that EB for all0 shows that
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