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Find the critical value for each of the following condition in a one way lindependent ANOVA k 5,n 5 with an alpha of 0.05 48
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Answer #1

In 1. Numerator df: k-1= 4,

n=5, so N= k*n= 25, so denominator df(N-k)= 25-5= 20

So critical value is at F4,20= 2.866 at alpha=0.05

2. Numerator df=11

Denominator df= 48-12= 36

So critical values is at F11,36 = 2.791 at alpha=0.01

3. Numerator df= 1

Denominator df= 10*2 - 2= 18

So F1,18 = 4.414 at alpha=0.05

4. Numerator df= 5

Denominator df= 2*6-6= 6

So F5,6= 8.746 at alpha=0.01

5. Numerator df= 7

Denominator df= 24-8 = 16

So F7,16 = 2.657 at alpha= 0.05

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