9)
Fe ----> Fe2+ + 2e- E0 = + 0.44 V
Cd2+ + 2e- ------> Cd E0 = - 0.4 V
so the total cell potential is , E0 = 0.44 - 0.4 = + 0.04 V
ΔG0 = - nFE0
here, n = 2 since the number of electrons transfer are two
ΔG0 = - 2 * 96485 * 0.04
= - 7718.8 J
ΔG0 = - 7.72 kJ
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