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9) Determine the value of AG° at 25 °C for Fe Fe2 Cd2|Cd
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Answer #1

9)

Fe ----> Fe2+ + 2e- E0 = + 0.44 V

Cd2+ + 2e- ------> Cd E0 = - 0.4 V

so the total cell potential is , E0 =  0.44 - 0.4 = + 0.04 V

ΔG0 = - nFE0

here, n = 2 since the number of electrons transfer are two

ΔG0 = - 2 * 96485 * 0.04

    = -  7718.8 J

ΔG0 = - 7.72 kJ

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