Question

intel) LEIL ofind allthe sked and evenbally ved part d the Dis.

Answer 1

x=1/2 and x=3/2 are fixed and eventually fixed points respectively.
We have to find all fixed and eventually fixed point of os fui= 10-11 e in R. solution To find fixed point ? Ret fao-x=0 = 12-1) - x = 0 - 0 It 2,1 => 11-1)=(x-1) Hence, from O, (2-1)-x = 0 -) -1 = 0 (Absurd). Here , fow has no fixed point greater than 1: If xxl 12-11 = -(2-1) z from 0, -1)-* =0 - 4+!-X20 = x= 1/3 is the only fixed point of fen =/x-11. To find eventually fixed point, Det a point no is called eventually fixed point of t. if f(n) = Y. & f(yo) = 9, where not yo. τ show point, we have to so to satisfy no to be E. fixed two condition. these

We can clearl eck . that Clearly from second condition, we can say that Yo is fixed point- and the only fixed point of few=pe-11 is. x= 1/2 so we need no sit fro)=1/3 st not - We can clearly check that f2) = k 44(1) but n=1/2 can't be E. fixed point as we need yo sot 2 f(x) = Yo st not yo > n = 3 ix Eventually fixed point os f (@) - ¢ ¢ ¢{}); } a xos j caly Eventually fixed point