The molar solubility of silver chromate Ag2CrO4 is 8.7 x 10-5 M. What is its Ksp?...

Question

Question

The molar solubility of silver chromate Ag2CrO4 is 8.7 x 10-5 M. What is its Ksp? A 2.1 x 10-11 B 1.3 x 10-12 C 6.6 x 10-13 D

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Answer 1

Answer #1

The molar solubility of Ag2CrO4 (S) = 8.7*10-5 M

one mole of Ag2CrO4 contains 2 moles of Ag+ and 1 mole of CrO42-.

So, molar solubility of Ag+ = [Ag+] = 2*S and molar solubility of CrO42- = [CrO42-] = S

Ksp = [Ag+]2 [CrO42-] = (2S)2* S = 4S3 = 4*(8.7*10-5)3 = 2.6*10-12

Answer 2

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