Question

If the Ksp of silver chromate (Ag2CrO4) is 1.1 x 10-12 and the silver ion concentration in the solution is 0.0005 M, what is the chromate ion concentration?

1.0 x 10-4 M

4.4 x 10-6 M

5.0 x 10-7 M

1.0 x 10-6 M

6.5 x 10-5 M

Answer 1

Concentration of chromate ion will be 4.4×10-6 M

9 write, Ag, Goa (5) = 2Ag* + Groot From the definition of solubility product, we can Ksp = [Agt ] 2 [Croan 7) 4.1.X 10-12(0.0005 je [Crown] -) [Croq 2-] = 1.1 X 10-12 = [Gr 04?] = 4.4 x 10-6.M. 2.5 x 10-7