Question

Find P of 2ohm resistor

ne 25 Je

Answer 1

Here for this circuit I apply node voltage method. I find voltage(v) for the circuit from that I solved remaining parameters.
4 ohm resistor parallel with 4 times 4/4 + 4 = 16/8 = 2 4 ohm resistor Node method KCL v' = IR = 1 (2) v/2 + v + 8/2 + 2v' = 0 I = v + 8/2 v/2 + v + 8/2 + 2 (v + 8) = 0 v' = (v + 8/2) times v/2 + v/2 + 4 + 2v + 16 = 0 v' = v + 8 v + 4 + 2v + 16 = 0 v' = v + 8 v + 4 + 2v + 16 = 0 3v = -20 = -20 + 24/3 v = -20/3 v' = 4/3 I = -20/3 + 8/2 = -20 + 24/3 times 2 = 4/6 = 2/3 = I \r\n P_2 ohm = V' I = V' 2/R = I^2 R = 4/3 times 2/3 = (4/3)^2/2 = 8/9 = 16/9 times 2 = 16/18 = 8/9 Power dissipated in P_2 ohm = 8/9 watts