Question

Given a set of 41 samples with a sample average of 33, and a sample deviation of 6.9, determine the 2-sided confidence interv
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Sduti on マ= 33, 5-D(= 6-9 in=u -1 ニuD Here ニ M-1ニ I684 At 90% Confidente tal The 901. C- 1 f 6.9 33土 1-68u 31: 1853, 3u 8t7 -

Add a comment
Know the answer?
Add Answer to:
Given a set of 41 samples with a sample average of 33, and a sample deviation...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • It is not asking to plug in the lower bound from the range of " upper...

    It is not asking to plug in the lower bound from the range of " upper and lower" It is asking only to calculate a one sided Thank you QUESTION 2 Given a set of 48 samples with a sample average of -11, and a sample deviation of 9.6, determine a lower bound on the population mean assuming a 99% confidence level. QUESTION 3 Given a set of 4 samples with a sample average of 0, and a sample deviation...

  • Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence...

    Use the​ one-mean t-interval procedure with the sample​ mean, sample​ size, sample standard​ deviation, and confidence level given below to find a confidence interval for the mean of the population from which the sample was drawn. sample mean=3.0 n=41 s=5.4 confidence level=90​% The 90​% confidence interval about μ is ?? to ???

  • 33. Sally draws a simple random sample from an original population. Sample size is n=41 and...

    33. Sally draws a simple random sample from an original population. Sample size is n=41 and sample size mean=130, and the sample standard deviation is s=6. FInd the 99% confidence interval for the population mean "u".

  • A biologist examines 6 geological samples for lead concentration. The mean lead concentration for the sample...

    A biologist examines 6 geological samples for lead concentration. The mean lead concentration for the sample data is 0.714 cc/cubic meter with a standard deviation of 0.0126. Determine the 90% confidence interval for the population mean lead concentration. Assume the population is approximately normal. Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places. A biologist examines 6 geological samples for lead concentration. The mean lead concentration for the sample...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the​ 90% and​ 95% confidence intervals for the population mean. Which interval is​ wider? If​ convenient, use technology to construct the confidence intervals. A random sample of 43 gas grills has a mean price of ​$626.50. Assume the population standard deviation is ​$58.70. The​ 90% confidence interval is ​( , ). ​(Round to one decimal place as​ needed.) The​ 95% confidence interval is ​(...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence ntervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals A random sample of 45 home theater systems has a mean price of $138.00. Assume the population standard deviation is 516.40. Construct a 90% confidence interval for the population mean. The 90% confidence interval...

  • Given two dependent random samples with the following results: Population 1 41 33 18 34 42...

    Given two dependent random samples with the following results: Population 1 41 33 18 34 42 39 50 Population 2 50 29 29 28 47 24 44 Use this data to find the 95% confidence interval for the true difference between the population means. Let d=(Population 1 entry)−(Population 2 entry) . Assume that both populations are normally distributed. Step 1 of 4: Find the mean of the paired differences, d ‾ . Round your answer to one decimal place. Step...

  • A sample of 41 running participants required an average time of 105 minutes to complete the...

    A sample of 41 running participants required an average time of 105 minutes to complete the race with a standard deviation of 20 minutes. (1) What is the lower and upper limits of a 90% confidence interval for the population mean

  • AM You are given the sample mean and the population standard deviation. Use this information to...

    AM You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 35 home theater systems has a mean price of $144.00. Assume the population standard deviation is $15.60. Construct a 90% confidence interval for the population mean. The 90% confidence...

  • You are given the sample mean and the population standard deviation. Use this information to construct...

    You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. From a random sample of 64 dates, the mean record high daily temperature in a certain city has a mean of 85.80°F. Assume the population standard deviation is 15.07°F. The 90% confidence interval is (ID). (Round to two decimal places as needed.) The...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT