Homework Answers
Field due to currnt carrying wire at a distance d is B =
mu_o*I/(2*pi*d)
so due to wire 1,magnetic field is B1 = mu_o*I1/(2*pi*d1) =
(2*10^-7*2)/(2) = 2*10^-7 T downwards
due to wire 2 ,B2 = mu_o*I1/(2*pi*d2) = (2*10^-7*6)/2 = 6*10^-7 T upwards
net magnetic field is B = B2-B1 = (6-2)*10^-7 = 4*10^-7 T upwards
Net force on wire 2 is F = i*L*B*sin(90) = 4*5*4*10^-7*sin(90) = 8*10^-6 N
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