Question

The two charges in Fig.-1 are separated by a distance d = 1.00 cm, and Q = +5.00 Find the magnitude of the electric field at point A due to 2Q A) 4.50 times 10^5 V B) 4.50 times 10^5 J C) 4.50 times 10^5 N D) 4.50 times 10^5 N/C. Calculate the electric potential at point B due to Q. A) 3.18 times 10^3 V B) 3.18 times 10^3 V c) 3.18 times 10^3 V D) 3.18 times 10^3 V E) None What is the magnitude of the electric force between the two charges? A) 4.50 times 10^6 N B) 4.50 times 10^9 V C) 4.50 times 10^3 N D) 4.50 times 10^8 N E)

Answer 1