Question

C++ program

Write a program that does the following: n main0 1. Prompts the user to enter the height, length, and depth of a cube 2. Calls a function that will reduce the size of the height, length, and depth by half (ie. divide them each by 2 arguments must be passed using references handle possible resulting decimal values (ie. 3/2-1.5) 3. Calls another function that will calculate and return the volume of the 'reduced' cube -arguments must be passed by value 4. Display the new height, length and volume of the cube ie. Height: 2.5 Length: 9 Depth: 3 Volume: 67.5 The volume should be a float displaying 1 digit of precision

Answer 1

#include<iostream>
#include<iomanip>

using namespace std;

//Function to reduce dimensions by half
void reduceHalf(float &height, float &length, float &depth)
{
   height /= 2;
   length /= 2;
   depth /= 2;
}

//Function to calculate and return volume of cube
float volumeOfCube(float height, float length, float depth)
{
   return (height * length * depth);
}

int main(void)
{
   float height, length, depth, volume;
  
   //Prompt user to enter dimensions of cube
   cout<<"Enter height: ";
   cin>>height;
   cout<<"Enter lenght: ";
   cin>>length;
   cout<<"Enter depth: ";
   cin>>depth;
  
   reduceHalf(height, length, depth);//Reduce dimensions by half
  
   volume = volumeOfCube(height, length, depth);
  
   cout<<"Height: "<<height;
   cout<<" Lenght: "<<length;
   cout<<" Depth: "<<depth;
   cout<<" Volume: "<<setprecision(1)<<fixed<<volume;//Print volume with precision of 1 digit
  
   return 0;
}

OUTPUT: