A geneticist has found 2 independent true breeding strains of mice that are completely hairless. Both...
A geneticist has found 2 independent true breeding strains of mice that are completely hairless. Both mutations are recessive to wild-type. When mice of the 2 diff hairless strains are crossed to each other, all the mice have hair, ie, they have the wild type phenotype. Based on this evidence, what is the minimum number of genes that can mtate to give hairless phentoype? when wildtype F1 mice of the cross bt the 2 hairless strains are crossed to generate an F2gen, what fraction of the offspring would you expect to be hairless? The answer is 2 and 7/16 but need to know HOW to get the answers. Thanks!
Homework Answers
Suppose one mice with naked strain having allele n and normal allele N
Another mice hair less having h for hairless H normal allele.Cross between will normal hair bearing phenotype.
nnH . X NN hh
F . NnHh which has normal wild type phenotype I.e having hair.
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A geneticist has found 2 independent true breeding strains of
mice that are completely hairless. Both...
46. (7 points) Vanessa has obtained two true-breeding strains of mice, each homozygous for an independently...
46. (7 points) Vanessa has obtained two true-breeding strains of
mice, each homozygous for an
independently discovered recessive mutation that prevents the
formation of hair on the body.
One of the mutant strains is called naked, and the other mutation
strain is called hairless. To
determine whether the two mutations are simply alleles for the same
gene, Vanessa crosses
naked and hairless mice with each other (cross 1). All the
offspring are phenotypically wild-
type.
A) What is the most...
Paragraph Styl VI. Vivien has obtained two true-breeding strains of mice, each homozygous for an independently...
Paragraph Styl VI. Vivien has obtained two true-breeding strains of mice, each homozygous for an independently discovered recessive mutation that prevents the formation of hair on the body The discoverer of one of the mutant strains calls his mutation naked, and the other researcher calls her strain hairless. To determine whether the two mutations are simply alleles for the same gene, Viviane crosses naked and hairless mice with each other. All the offspring are phenotypically wild-type. After intercrossing these F1...
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Answer Choices: A) Only one of the strains has a mutation in an eye color gene....
Answer Choices:
A) Only one of the strains has a mutation in an eye color
gene.
b) Strains C and D have mutations in different genes.
C) Strains C and D have mutations in the same gene.
D) More information is needed to infer the location of
mutations.
! Required information Fruit flies normally have red eyes. Seven different true-breeding strains of fly with white eyes have been identified (A–G). In each strain, the white eye trait is due to...
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please help with part A and B. 2. A yeast geneticist isolates two different haploid mutant...
please help with part A and B.
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Arabidopsis thaliana, a plant, has small leaf projections called trichomes. A search for mutants revealed two...
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You are interested in mouse eye development and conduct a genetic screen for mutations that result...
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46. (7 points) Vanessa has obtained two true-breeding strains of
mice, each homozygous for an
independently discovered recessive mutation that prevents the
formation of hair on the body.
One of the mutant strains is called naked, and the other mutation
strain is called hairless. To
determine whether the two mutations are simply alleles for the same
gene, Vanessa crosses
naked and hairless mice with each other (cross 1). All the
offspring are phenotypically wild-
type.
A) What is the most...
Paragraph Styl VI. Vivien has obtained two true-breeding strains of mice, each homozygous for an independently discovered recessive mutation that prevents the formation of hair on the body The discoverer of one of the mutant strains calls his mutation naked, and the other researcher calls her strain hairless. To determine whether the two mutations are simply alleles for the same gene, Viviane crosses naked and hairless mice with each other. All the offspring are phenotypically wild-type. After intercrossing these F1...
Required information Fruit flies normally have red eyes. Seven different true-breeding strains of fly with white eyes have been identified (A-G). In each strain, the white eye trait is due to an autosomal recessive allele. It is possible all seven strains have mutations in the same gene. Alternatively, they may have mutations in different genes. To determine how many genes are involved in eye color in these flies, pair-wise crosses are performed between each strain. The offspring phenotypes resulting from...
25. A cross is made between two different true-breeding strains of daylilies, both of which have white flowers. All of the F1 generation plants have yellow flowers. When an F, offspring is crossed with either one of the parental strains, half of the offspring have yellow flowers and half of them have white flowers. Propose an explanation for this outcome. In your answer, you should describe the genotypes of the two parental strains and the F1 offspring, and also explain...
Answer Choices:
A) Only one of the strains has a mutation in an eye color
gene.
b) Strains C and D have mutations in different genes.
C) Strains C and D have mutations in the same gene.
D) More information is needed to infer the location of
mutations.
! Required information Fruit flies normally have red eyes. Seven different true-breeding strains of fly with white eyes have been identified (A–G). In each strain, the white eye trait is due to...
3. (2pts) A group of researchers working with Arabidopsis (a small weedy plant that is widely used as model organism by plant geneticists) is isolating new mutations that cause extra petals to be formed on the flowers. They isolate six plants from different mutagenesis experiments that all show the desired phenotype. They then establish true breeding strains A-F by self-fertilizing and further inbreeding the plants. They also established that the mutations in the strains were recessive, and gave a 3:1...
please help with part A and B.
2. A yeast geneticist isolates two different haploid mutant yeast strains, Strain A and Strain B, which cannot grow unless the amino acid leucine is added to the growth media. Wild-type yeast strains can make their own leucine and do not require that it be added to the growth media. The geneticist discovers that each mutant yeast strain contains a single recessive mutation that leads to the observed leucine-requiring phenotype. When she crosses...
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(blue and red of the wild type pathways shown 5.(9.5 points) Hagrid has introduced a new course at Hogwarts: Genetics of a Through their experiments, the fifth years have discovered that flobberw in years have discovered that flobberworms are normally purple, with pigmentation controlled by mixing the end products (blue and red of the wild type below). Through genetic experiments, they've discovered that the step su genetic experiments, they've discovered that the steps of the pathways are controlled by 3...
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