Question

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EXPERIMENTAL PRO CEDURE A. Osmosis and Osmotic Pressure If two solutions of different concentration are separated by a semiperme- able membrane through which solvent (but not solute) can flow, solvent will flow from the dilute solution into the concentrated solution. The pressure necessary to prevent solvent flow between such a pair of solutions is called the osmotic pressure of the system and depends on the solute concentration difference between the two solutions. In this part of the experiment, the magnitude of the osmotic pressure will not be measured, but the associated flow of solvent through membranes will be illustrated.

Answer 1

The answer is (d). Both samples would remain essentially constant in mass

Explanation: When you misplaced the dialysis tube sample, what was done is " dialysis tube with water was kept in beaker with water, while dialysis tube with sugar solution was kept in beaker with sugar solution".

For the case of sugar solution in beaker and sugar solution in dialysis tube. No movement of solvent molecules will occur via semi-permiable membrane, as the concentration of the two sugar solutions are same. Which means there is no concentration difference between the two solutions (the one in dialysis tube and other in beaker). So, the two sugar solutions are isotonic in nature (same osmotic pressure). As, no movement of solvent occurred, mass of sample will remain unchanged.

For the case of water in beaker and water in dialysis tube. No movement of solvent molecules will occur via semi-permiable membrane, as the there is no solute to and its pure solvent. Which means there is no concentration difference between the two solutions (the one in dialysis tube and other in beaker). So, again same osmotic pressure. As, no movement of solvent occurred, mass of sample will remain unchanged.