Question

Question 2 Integrated rate law The other method to establish rate laws is to measure the remaining concentrations of a reactant at different times during the reaction. The concentrations of reactant for reaction A 2B + C measured as a function of time at 25°C are listed in the following table. t(s) 15 25 35 45 55 [A] (M) 0.30 0.26 ? 0.20 0.17 (s) [A] (M) 65 0.15 75 0.13 85 0.11 95 0.10 105 0.09 (a) Use Excel to construct three plots, sketch the plots in the following frames. y-axis: A. 4-axis: In (A -axis I-axist x-axis: t (b) Determine the order of the reaction using the plots in part (a). Explain why. (c) Use Excel to determine the rate constant of the reaction with the plots in part (a) (including the unit) (d) Use Excel to determine the initial concentration of the reactant with the plots in part (a).

Answer 1

Formulas Data Review View Help File N12 A 1. t(s) Home Insert Page Layout - fix B C D [A] In[A] 1/[A] 15 0.3 1.20397 -0.83058 25 0.26 -1.34707 -0.74235 E F G H I J PLOT OF (A) VS TIME 0.35 0.3 0.25 45 55 0.2 65 0.2 -1.60944 -0.62133 0.17 -1.77196 -0.56435 0.15 -1.89712 -0.52711 0.13 -2.04022 -0.49014 0.11 2.20727 -0.45305 0.1 -2.30259 -0.43429 0.09 -2.40795 -0.41529 75 85 0.15 0.1 95 11 105 0.05 40 60 80 100 120 13 14 plot of In [A] VS TIME PLOT OF 1/ [A] vs time 40 80 100 40 60 80 1 00 120 -0.1 0 -0.2 -0.3 -0.6 -0.7 -0.8 -0,9 Sheet1 Type here to search Ei e

for the given seaction A +18) (2 ) 15 28+ 25 35 55 65 75 0:15 0:13 85 95 105 0.10 0-09 (6) The order of the reaction is 1st order As the (200) In [A] Vs time is a straight line quanh which is fulfilled by the first onder de acho The rate equation is represented as 10-X nehere Q = {vutial concentration Boch = amount of product Pound R = Rate constant t = time In(a-x) = -Rt + boga inal Ty = mxtc where

y dependant variable x Independant variable c - constant ms scope le) Rale con stant is respuesented by stope scope = -k The equation of the graph is y = -0.0137% -1.6073 de = 0.01375-17 (d) Initial concentration is 'a' In a = -1.0073 Ta = 0·36 52 MI

PLOT OF LN [A] VS TIME y=-0.0137x-1.0073 60 100 -0.5