Question

A. 1x10-10 m/s A 0.65 mm diameter copper wire carries a tiny current of 2.3 uA. Estimate the electron drift velocity. B. 7x10-10 m/s O C. 2x10-10 m/s O d. 5.1x10-10 m/s

Answer 1

Solution) d = 0.65 mm = 0.65×10^(-3) m

i = 2.3 uA = 2.3×10^(-6) A

Drift velocity , Vd = ?

i = neA(Vd)

Vd = (i)/(neA)

n = (N/m)(density)

N = avogadro number = 6.023×10^(23)  

m = 63.5×10^(-3) kg

Density = 8.9×10^(3) kg/m^3

n = (6.023×10^(23)×8.9×10^(3))/(63.5×10^(-3))

n = 0.844×10^(29)

e = 1.6×10^(-19) C

A = ((pi)(d^2))/(4)

A = ((pi)(0.65×10^(-3))^2)/(4)

A = 0.332×10^(-6) m^2

Vd = (i)/(neA)

Vd = (2.3×10^(-6))/(0.844×10^(29)×1.6×10^(-19)×0.332×10^(-6))

Vd = 5.1×10^(-10) m/s