Given a day, month, and year, calculate the day of the week corresponding to that date...
Given a day, month, and year, calculate the day of the week corresponding to that date without using the Python DateTime class.
Homework Answers
def weekDay(year, month, day):
offset = [0, 31, 59, 90, 120, 151, 181, 212, 243, 273, 304, 334]
week = ['Sunday',
'Monday',
'Tuesday',
'Wednesday',
'Thursday',
'Friday',
'Saturday']
afterFeb = 1
if month > 2: afterFeb = 0
aux = year - 1700 - afterFeb
# dayOfWeek for 1700/1/1 = 5, Friday
dayOfWeek = 5
# partial sum of days betweem current date and 1700/1/1
dayOfWeek += (aux + afterFeb) * 365
# leap year correction
dayOfWeek += aux / 4 - aux / 100 + (aux + 100) / 400
# sum monthly and day offsets
dayOfWeek += offset[month - 1] + (day - 1)
dayOfWeek %= 7
return week[dayOfWeek]
print weekDay(2013, 6, 15)
print weekDay(1969, 7, 20)
print weekDay(1945, 4, 30)
print weekDay(1900, 1, 1)
print weekDay(1789, 7, 14)
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