Question

using C programming

Date Write a program that reads a month and a day in that month and prints the date in format "month day". The input is two integers, one between 1 and 12 (inclusive) and one between 1 and 31 (inclusive) and the output is a single line in format "month day". For example, for input 2 10 the program will print "February 10th". The day will always have the ordinal indicator, e.g. 1st, 2nd, 3rd, 4th. Example of input: 52 Corresponding output: May 2nd Example of input: 12 11 Corresponding output: December 11th

Answer 1

CODE:

#include <stdio.h>
int main(){
   char *months[] = {"January","February","March",
                                       "April","May","June","July",
                                       "August","September","October",
                                       "November","December"};

   int month,day;
   scanf("%d %d",&month,&day);

   printf(" %s ",months[month-1]);
   if(day==1 || day==21 || day==31){
       printf("%dst",day);
   }
   else if(day==2 || day==22){
       printf("%dnd",day);
   }
   else if(day==3 || day==23){
       printf("%drd",day);
   }
   else{
       printf("%dth",day);
   }
   return 0;
}

SCREENSHOT:

1 main.c #include <stdio.h> 2. int main() { 3 char *months[] = {"January", "February", "March", 4 "April", "May", "June", "July", "August", "September", "October", "November", "December"}; 7 8 int month, day; 9 scanf("%d %d",&month, &day); 10 11 printf(" %s ", months[month-1]); 12 if(day==1 || day==21 || day==31) { 13 printf("%dst", day); 14 } 15 else if(day==2 || day==22){ 16 printf("%dnd", day); 17 18 else if(day==3 || day==23) { 19 printf("%drd", day); 20 21 else{ 22 printf("%dth", day); 23 } 24 return 0; 25 } } } input 5 12 May 12th ... Program finished with exit code o Press ENTER to exit console.

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