Question

Question 1: Write a program in C that reads a date from the keyboard and tests whether it contains a valid date. Display the date and a message that indicates whether it is valid. If it is not valid, also display a message explaining why it is not valid. The input date will have the format:

mm/dd/yyyy

Note that there is no space in the above format. A date in this format must be entered in one line.

A valid month value mm must be from 01 to 12 ( January is 01). The day value dd must be from 01 to a value that is appropriate for the given month. September, April, June, and November each have 30 days. February has 28 days except for leap years when it has 29. The remaining months all have 31 days each. For the sake of simplicity assume the year is a leap year.

Note: It is an error if the user enters any other character in place of: /.

Hints:

Your program can read a date with one scanf and 3 variables.

Answer

Answer 1

#include <stdio.h>

int main()
{
//variable declaration
int dd,mm,yy;

//display message
printf("Enter date (mm/dd/yyyy): ");
scanf("%d/%d/%d",&mm,&dd,&yy);

//check year value
if(yy<1000 || yy>9999)
{
printf("The year value is not valid.");
return 0;
}
  
//check month value
if(mm<1 || mm>12)
{
printf("Month is not valid.");
return 0;
}
  
//check day value
if((dd>=1 && dd<=31) && (mm==1 || mm==3 || mm==5 || mm==7 || mm==8 || mm==10 || mm==12))
{
printf("The date: %d/%d/%d is valid", mm, dd, yy);
}
else if((dd>=1 && dd<=30) && (mm==4 || mm==6 || mm==9 || mm==11))
{
printf("The date: %d/%d/%d is valid", mm, dd, yy);
}
else if((dd>=1 && dd<=29) && (mm==2))
{
printf("The date: %d/%d/%d is valid", mm, dd, yy);
}
else
{
printf("Day is not valid");
}
  
return 0;
}

OUTPUT:

Enter date (mm/dd/yyyy): 10/10/1999 The date: 10/10/1999 is valid

Enter date (mm/dd/yyyy): 13/10/2000 Month is not valid.